I drop and re-register a serviced component every time there is a new method
or a change in the parameters of an existing method.
I found out that even if I keep the old version of the component in COM+ and
simply replace the assembly, it still works. I don't use COM+ clients, so

All,
I have a servicedcomponet that works fine if its activated as library app,
but doesn't work if its activated as a server component.
I get the following error :

Hi all,
I'm having a strange problem whith an application I'm developing using
COM Components. This is the situation:
COM+ Application 1 with components:

Has ANYBODY got BYOT.CreateWithTipTransaction to work? I've tried to
implement this method in many different ways. With the current way I
implement this method, the following error is logged into my Windows
event viewer (using Windows XP - however, I get a very similar error

I am trying to create a Transaction Broker component that can be
instantiated to "setup" a new transaction.  Once the TransBroker establishes
a new transaction, I would like to call my other serviced components and
have them enlist in the transaction of the TransBroker.

When I place my components in COM+ (in Server mode), they fail to pick up
and read the APP.CONFIG file.  Of course, when the apps run in the memory
process of the client, all is well an dandy as the DB settings are picked up
just fine using :

Currently i have an existing application that using an admin serviced component, I would like to use the same serviced component in another application.How should i go about doing it??Both apps reside on the same machine.
Thanks.
Regards,
Cindy See

Has anyone seen this issue? I have an XML document that I am looping through nodes to get attribute values. My class is derived from ServicedComponents (a requirement for Biztalk). When I run through the debugger, I can see the attribute values in the 'Locals' list but I am ...

?

How to create COM+ object which use .NET EnterpriceServices on remote
machine?
I use on remote machine:
object comObject;