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.NET Forum / Windows Forms / Design Time / September 2004

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Visible Property returns wrong value in Designer

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- 02 Sep 2004 17:32 GMT
Hello

I need to get the Visible property of a Control at Designtime.

I have wrote a Designer by Inheriting a
"Windows.Forms.Design.DocumentDesigner".

In side this Class I loop throw the Child Controls of the Form.

But the Visible  Attrbute always return "true" and not the Value set in the
Property Grid.

I read that this is done via Metadata Filtering to avoid taht the Control is
hidden

at the Designer if you set it to "False"

But how can I get the real value (the Value from the Propertygrid) ???

Thanx for any Idea :-)
Frank Hileman - 02 Sep 2004 21:58 GMT
TypeDescriptor.GetProperties(control)["Visible"].GetValue(control);

Regards,
Frank Hileman

check out VG.net: www.vgdotnet.com
Animated vector graphics system
Integrated Visual Studio .NET graphics editor
> Hello
>
[quoted text clipped - 16 lines]
>
> Thanx for any Idea :-)
- 03 Sep 2004 08:59 GMT
Thanx, that's it !!

>>www.vgdotnet.com

Cool Thing !

> TypeDescriptor.GetProperties(control)["Visible"].GetValue(control);
>
[quoted text clipped - 26 lines]
> >
> > Thanx for any Idea :-)

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