How do I access a reference in XmlSchema?

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David Thielen - 30 Jun 2007 23:58 GMT

I have an xsd:
    <xsd:element name="comment" type="xsd:string">
        <xsd:annotation>
            <xsd:documentation>hi there</xsd:documentation>
        </xsd:annotation>
    </xsd:element>
    <xsd:complexType name="PurchaseOrderType">
        <xsd:sequence>
            <xsd:element name="shipTo" type="USAddress"/>
            <xsd:element name="billTo" type="USAddress"/>
            <xsd:element ref="comment" minOccurs="0"/>
            <xsd:element name="items" type="Items"/>
        </xsd:sequence>
        <xsd:attribute name="orderDate" type="xsd:date"/>
    </xsd:complexType>

that I load into an XmlSchema object. One of the inner elements uses a
ref="comment" instead of a name=. Do I need to then walk the entire tree in
the XmlSchema to get the reference, or walk all the top level elements, or is
there a property I can use to access it directly?

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thanks - dave
david_at_windward_dot_net
http://www.windwardreports.com

Cubicle Wars - http://www.windwardreports.com/film.htm

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John Saunders [MVP] - 01 Jul 2007 02:15 GMT

>I have an xsd:
> <xsd:element name="comment" type="xsd:string">
[quoted text clipped - 18 lines]
> is
> there a property I can use to access it directly?

ref can only refer to global elements. You only need to look at the
XmlSchemaSet.GlobalElements collection to see the possible root elements.

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John Saunders [MVP]

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David Thielen - 01 Jul 2007 19:12 GMT

Worked great - thanks.

I assume from the documentation when I see this that I ignore the properties
in the initial element (except for min/max/id if set) and instead the
reference is the element at this position and the reference then gives me any
attributes and child elements???

Signature

thanks - dave
david_at_windward_dot_net
http://www.windwardreports.com

Cubicle Wars - http://www.windwardreports.com/film.htm

> >I have an xsd:
> > <xsd:element name="comment" type="xsd:string">
[quoted text clipped - 21 lines]
> ref can only refer to global elements. You only need to look at the
> XmlSchemaSet.GlobalElements collection to see the possible root elements.

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WenYuan Wang [MSFT] - 03 Jul 2007 11:17 GMT

Hello Dave
Thanks for John's idea.
XmlSchemaSet.GlobalElements is the best way to search the reference.

The schema you posted in newsgroup is equal to
<xsd:complexType name="PurchaseOrderType">
        <xsd:sequence>
            <xsd:element name="shipTo" type="USAddress"/>
            <xsd:element name="billTo" type="USAddress"/>

            <xsd:element name="comment" type="xsd:string" minOccurs="0">
                    <xsd:annotation>
                        <xsd:documentation>hi there</xsd:documentation>
                    </xsd:annotation>
            </xsd:element>

            <xsd:element name="items" type="Items"/>
        </xsd:sequence>
        <xsd:attribute name="orderDate" type="xsd:date"/>
</xsd:complexType>

If you get the reference, it will tell you all child element and
attributes. However, please don't forget the attribute in the initial
element. (such as the minOccurs="0" in the current case)

Hope this helps.
Sincerley,
Wen Yuan
Microsoft Online Community Support
==================================================
This posting is provided "AS IS" with no warranties, and confers no rights.

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hgbjxeiluw - 26 Aug 2007 03:26 GMT

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How do I access a reference in XmlSchema?

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