Hi, i have the following xsl file
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<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="FirstLetter"></xsl:param>
<xsl:template match="customerlist">
<html>
<body>
<table border="1" frame="box">
<tr>
<TH>Customer</TH>
<TH>Number</TH>
<TH>Address</TH>
</tr>
<xsl:for-each select="mag_customer[substring(@customer,1,1) =
$FirstLetter]">
<tr>
<td>
<xsl:value-of select="@customer"/>
</td>
<td>
<xsl:value-of select="@customer_number"/>
</td>
<td>
<xsl:value-of select="@address"/>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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what i want from this file is to ref to another page, so if user
clicked "customer" filed, it will go to the selected customer detail
information page. can i do this?
Martin Honnen - 28 Jul 2006 17:10 GMT
> what i want from this file is to ref to another page, so if user
> clicked "customer" filed, it will go to the selected customer detail
> information page. can i do this?
Your XSLT stylesheet generates a HTML document, so simply make it
generate a HTML document with a HTML link e.g.
<a href="showDetails.aspx?customer_number={@customer_number}">
<xsl:value-of select="@customer_number"/>
</a>
Of course you need to implement showDetails.aspx then.

Signature
Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/
Wang Xiaoning - 28 Jul 2006 19:13 GMT
thanks, it works perfect.