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.NET Forum / .NET Framework / XML / February 2007XmlNode.SelectNodes, order of nodes
If I execute XmlNode.SelectNodes("some xpath query") and then use foreach to iterate over it. Will it guaratee that the order of nodes I get will be same as the order of nodes in the original xml document? Can someone point me to a document which states that the order is (or is not) guarateened (I could not find any when i did my search on msdn). This is very crucial to our design, otherwise I will have to add a "sequence" attribute and then order by the sequence. Thanks in advance.  SignatureVikram Vamshi Database Engineer Eclipsys Corporation > If I execute XmlNode.SelectNodes("some xpath query") and then use foreach to > iterate over it. > Will it guaratee that the order of nodes I get will be same as the order of > nodes in the original xml document? I think XPath rules will apply so on e.g. the child axis the nodes will be in document order, on e.g. the preceding-sibling axis the nodes will be in reversed document order. See the XPath specification <http://www.w3.org/TR/xpath#axes>, an excerpt says: "An axis is either a forward axis or a reverse axis. An axis that only ever contains the context node or nodes that are after the context node in document order is a forward axis. An axis that only ever contains the context node or nodes that are before the context node in document order is a reverse axis. Thus, the ancestor, ancestor-or-self, preceding, and preceding-sibling axes are reverse axes; all other axes are forward axes. Since the self axis always contains at most one node, it makes no difference whether it is a forward or reverse axis." SignatureMartin Honnen --- MVP XML http://JavaScript.FAQTs.com/ Martin, I did read the document, from what I understand it says that the nodes in the node-set are based upon the axis that you select. Howerver it does not impose any ordering on the nodes within the final node-set. So the 'axis' simply acts like a filtering mechanism. Did I misinterpret it? Thanks for taking your time to respond. Vikram SignatureVikram Vamshi Database Engineer Eclipsys Corporation > >> If I execute XmlNode.SelectNodes("some xpath query") and then use foreach [quoted text clipped - 16 lines] > Since the self axis always contains at most one node, it makes no > difference whether it is a forward or reverse axis." > If I execute XmlNode.SelectNodes("some xpath query") and then use foreach to > iterate over it. [quoted text clipped - 6 lines] > This is very crucial to our design, otherwise I will have to add a > "sequence" attribute and then order by the sequence. http://msdn2.microsoft.com/en-us/microsoft.office.interop.word.xmlnode.selectnod es.aspx "Returns a XMLNodes collection that represents all the nodes that match a specified XPath string in the order in which they appear." SignatureOleg Tkachenko [XML MVP, MCAD] http://www.XmlLab.Net | http://www.XLinq.Net | http://blog.tkachenko.com That is from the word interop documentation, do you think the same will hold true for the .net 2.0 framework. SignatureVikram Vamshi Database Engineer Eclipsys Corporation >> If I execute XmlNode.SelectNodes("some xpath query") and then use foreach >> to iterate over it. [quoted text clipped - 11 lines] > "Returns a XMLNodes collection that represents all the nodes that match a > specified XPath string in the order in which they appear." > That is from the word interop documentation, do you think the same will hold > true for the .net 2.0 framework. Yes. But if your whole design depends on this feature you better sort selected nodes explicitly. XmlNode.SelectNodes is just a wrapper for XPathNavigator.Select, so instead SelectNodes use XPathNavigator, compiled XPathExpression and AddSort() method to sort nodes by preceding nodes count. SignatureOleg Tkachenko [XML MVP, MCAD] http://www.XmlLab.Net | http://www.XLinq.Net | http://blog.tkachenko.com Thanks!!! SignatureVikram Vamshi Database Engineer Eclipsys Corporation >> That is from the word interop documentation, do you think the same will >> hold true for the .net 2.0 framework. [quoted text clipped - 4 lines] > XPathExpression and AddSort() method to sort nodes by preceding nodes > count. Hi, Nice Replies those are worth ful.. Please have a look at my blog http://dotnethangout.blogspot.com/2007/02/xml-in-net.html Please Visit http://dotnethangout.blogspot.com/2007/02/xml-in-net.html Free MagazinesGet these publications absolutely FREE for up to 12 months. There are no hidden fees and no obligation. Simply choose a title, complete the application form and submit it. Read more ...
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