extern "C" is ignored

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Toto - 26 Sep 2007 13:06 GMT

Hello,

My DLL (VC 2005, unmanaged) contains an exported function AutoOpen, whose name
should be undecorated. I've used this declaration:

extern "C" __declspec(dllexport) int WINAPI AutoOpen(void)

In spite of extern "C", the name of this function is still decorated in the DLL
(_AutoOpen@0 instead of AutoOpen). Why ?

Thanks !

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Jochen Kalmbach [MVP] - 26 Sep 2007 13:14 GMT

Hi Toto!

> extern "C" __declspec(dllexport) int WINAPI AutoOpen(void)
>
> In spite of extern "C", the name of this function is still decorated in
> the DLL (_AutoOpen@0 instead of AutoOpen). Why ?

This is the default naming if you choose 'extern "C"'.

If you want other names, you must use a *.def file!

Greetings
Jochen

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Ben Voigt [C++ MVP] - 26 Sep 2007 17:30 GMT

> Hi Toto!
>
[quoted text clipped - 4 lines]
>
> This is the default naming if you choose 'extern "C"'.

Well, that is the combination of extern "C" with __stdcall (which is part of
WINAPI). It definitely is not the C++ mangled name, which encodes all
parameters, namespace, and so forth.

> If you want other names, you must use a *.def file!

Yes, and also allows you to control ordinals, etc.

> Greetings
> Jochen

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extern "C" is ignored

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