void (Foo::^p)()=&Foo::bar; // won't compile

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Ray Tayek - 20 Mar 2006 20:34 GMT

hi, trying to make an array of function pointers to make delegates with.
but the compiler does not like: void (Foo::^p)()=&Foo::bar;

i did find an article that showed how to convert a delegate to a
function pointer, but i sorta want to go the other way around.

thanks

class Foo { public: void bar() {} };
class Baz {
    void qux() {
        void (Foo::*p)()=&Foo::bar; // works fine
    }
};
ref class RFoo { void bar() {} };
ref class RBaz {
    void qux() {
        void (Foo::^p)()=&Foo::bar; // C2589 C2143 C2059
    }
};

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Marcus Heege - 21 Mar 2006 19:42 GMT

> hi, trying to make an array of function pointers to make delegates with.
> but the compiler does not like: void (Foo::^p)()=&Foo::bar;
[quoted text clipped - 16 lines]
> }
> };

instead of your managed function pointer, you should define

delegate void MyDelegate();

Once you have done that, you can instantiate it:

MyDelegate^ d = gcnew MyDelegate(&RFoo::bar);

Once you have instantiate it, you can invoke it:

d->Invoke();

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Ray Tayek - 23 Mar 2006 04:13 GMT

> > hi, trying to make an array of function pointers to make delegates with.
> > but the compiler does not like: void (Foo::^p)()=&Foo::bar;
[quoted text clipped - 20 lines]
>
> delegate void MyDelegate(); ... you can invoke it:

yes, that works fine. i was hoping to initialize an array of function
pointers to use to create the delegate.

thanks

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void (Foo::^p)()=&Foo::bar; // won't compile

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