Hi Tom,

I see what you're saying, but what I need is the ability to find out the
number of elements in an *arbitrary* array. Put another way, when the number
of elements in the array is defined at runtime and is a variable.

This is exactly what I want to be able to do:

int Array_Size( Point point[] )
{
       return number_of_elements_in( point ) ;
}

To put this in context, I'm using the Graphics DrawPolygon method. Here it
takes as a parameter Point[], the list of the vertices of the polygon. But
the function does not take the number of elements in Point[] as a parameter,
hence DrawPoygon() must be able to figure out the number of elements in
Point[] just from Point[] (rather, an instance of). I need to be able to do
the same since I must process these points before I give them to
DrawPolygon, so of course I need to know the number of elements in Point[]
as well from the same info (i.e., I'm not given the Point array size in
number of elements).

My apologies, I was using it wrong. point->Length DOES work. Thanks! : )

[==P=]]

Hi James,

Unfortunately points->Length doesn't work, but instead generates the error:

C2039: 'Length' is not a member of 'System::Drawing::Point'.

And I've tried 'length', 'size', and 'Size' as well, with no luck.

There HAS to be  way to get the number of elements in a Point[] array, but
what is it?

[==P==]

Ok, got another question. How do I return a Point[] (pointer) from a method?
The following won't work:

Point[] Get_Points() { return m_Points ; } // error: Point[] is not a valid
syntax here

where m_Points is defined by:

Point m_Points[] ;

I CAN return a pointer to the first element of the list, but I'm guessing
this doesn't retain the array info (such as 'Length'....hehe). That is, I
CAN do the following:

Point* Get_Points() {  return &(m_Points[0]) ; }

Is there a way to return a pointer to an array of Point's? Will the above do
the trick and preserve its interpretation of the return value as a pointer
to an array, not just a single element (which I doubt, but it might know
from context)?

Thanks (again) in advance!  : )

[==P==]