Vector<E> -> E _

Vector<E> -> E __gc[]

Thread view:

Enable EMail Alerts

Start New Thread

Thread rating:

ravenous.wolves@gmail.com - 02 Mar 2005 21:05 GMT

I'm trying to create a template function to convert from a vector of
Es, to a managed array of Es. I want this to work with std::vector, or
any other type that implements the call requirements of this function.

I get the following error on this code:
error C2143: syntax error : missing ')' before '<'

    template<typename T, typename E>
    E ToManaged( T<E> const & crUnmanagedVec ) __gc[]
    {
        int nElements = crUnmanagedVec.size();
        E managedArray __gc[] = new E __gc[nElements];

        for( int i = 0; i < nElements; ++i )
        {
            managedArray[i] = crUnmanagedVec[i];
        }

        return managedArray;
    }

Reply to this Message

Carl Daniel [VC++ MVP] - 02 Mar 2005 22:10 GMT

> I'm trying to create a template function to convert from a vector of
> Es, to a managed array of Es. I want this to work with std::vector, or
[quoted text clipped - 4 lines]
>
> template<typename T, typename E>

template<template<class> T, typename E>

-cd

Reply to this Message

Carl Daniel [VC++ MVP] - 02 Mar 2005 23:57 GMT

>> I'm trying to create a template function to convert from a vector of
>> Es, to a managed array of Es. I want this to work with std::vector,
[quoted text clipped - 5 lines]
>
> template<template<class> T, typename E>

Err...

template<template<typename> class T, typename E>

HOWEVER, that won't work for std::vector. Sadly, the C++ standarization
committee made the regretable decision (IMO) to require template argument
lists for template template parameters to match exactly, rather than
requiring them to be compatible.

The template argument list for std::vector isn't simply <T>, rather, it's at
least <T,std::allocator<T> >. More unfortunately, implementors are allowed
to add additional template parameters with defaults, so in practice it's
impossible to match a standard container such as std::vector to a template
template argument in a portable way.

-cd

Reply to this Message

ben - 03 Mar 2005 10:44 GMT

would this work?

template <typename E, typename Policy = DefPolicy<E> >
class CToManaged
{
public:

E operator () (const typename Policy::ContainerType& crUnmanagedVec)
__gc[];
};

template <typename E>
class DefPolicy
{
public:
typedef std::vector<E> ContainerType;
//...
};

ben

> >> I'm trying to create a template function to convert from a vector of
> >> Es, to a managed array of Es. I want this to work with std::vector,
[quoted text clipped - 22 lines]
>
> -cd

Reply to this Message

Vector<E> -> E __gc[]

Free Magazines