Muti-parameter for System.diagnostics.process.start() ???

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kimiraikkonen - 30 Sep 2007 23:19 GMT

Hello,
I want to ask this:

If i do: System.Diagnostics.Process.Start("c:\lame", "--preset
standard c:\blabla.wav c:\blabla.mp3") it works.

But i don't want this. I want my 2 textboxes must take place as
variable like: System.Diagnostics.Process.Start("c:\lame", "--preset
standard textbox1" textbox1.text +
textbox2.text). But that doesn't work. Meanwhile textboxes are the
filename paths.

How can i run my process with more than one parameter using user
variables like placed in textboxes?

Very thanks.

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Family Tree Mike - 01 Oct 2007 01:35 GMT

This should work:

System.Diagnostics.Process.Start("c:\lame", _
"--preset standard textbox1" + textbox1.text + textbox2.text).

You were missing one plus sign. If you copied wrong and actually had the
plus sign, then it should have worked. You may need to quote some of the
strings, if they contain spaces. Spaces are assumed to separate the
arguments, so quoting it will allow for a space in an argument.

Hope this helps.

> Hello,
> I want to ask this:
[quoted text clipped - 12 lines]
>
> Very thanks.

Reply to this Message

Family Tree Mike - 01 Oct 2007 02:10 GMT

Andrew is correct, that there should be a + " " + between the two textbox
items.

> This should work:
>
[quoted text clipped - 24 lines]
> >
> > Very thanks.

Reply to this Message

rowe_newsgroups - 01 Oct 2007 11:26 GMT

On Sep 30, 9:10 pm, Family Tree Mike
<FamilyTreeM...@discussions.microsoft.com> wrote:

> Andrew is correct, that there should be a + " " + between the two textbox
> items.
[quoted text clipped - 27 lines]
>
> > > Very thanks.

For hard to read concatenations, I tend to use the String.Format()
option:

Process.Start("C:\lame", _
String.Format("--preset standard {0} {1}", textBox1.Text,
textBox2.Text))

(imo) It makes spacing and other concerns much easier to look at.

Thanks,

Seth Rowe

Reply to this Message

kimiraikkonen - 01 Oct 2007 19:13 GMT

Thanks all :) Multi-parameter launch is OK now but i couldn't hide my
process while processing. It's still shown on the screen.

Dim myProcess As System.Diagnostics.Process = New
System.Diagnostics.Process()
myProcess.StartInfo.WindowStyle =
System.Diagnostics.ProcessWindowStyle.Hidden
myProcess = System.Diagnostics.Process.Start("c:\lame",
"--preset standard" + textbox1.text + " " +
textbox2.text).
myProcess.WaitForExit()
MsgBox("Conversion Completed Successfully",
MsgBoxStyle.Information, "Completed")

Reply to this Message

Andrew Jackson - 01 Oct 2007 01:41 GMT

Looks to me you forgot one of your str concats

System.Diagnostics.Process.Start("c:\lame","--preset
standard"+textbox1.text+" "+textbox2.text)

> Hello,
> I want to ask this:
[quoted text clipped - 12 lines]
>
> Very thanks.

Reply to this Message

Andrew Jackson - 01 Oct 2007 01:42 GMT

Mybad you also probably need to put a space after standard in my reply
below.

System.Diagnostics.Process.Start("c:\lame","--preset standard
"+textbox1.text+" "+textbox2.text)

> Looks to me you forgot one of your str concats
>
[quoted text clipped - 17 lines]
>>
>> Very thanks.

Reply to this Message

Muti-parameter for System.diagnostics.process.start() ???

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