I have inherited this vb6 code which i am trying to rewrite using vb.net 2005
I need to be able to get this working as we cannot issue out new end user
software at the moment
Public Function Decript(String1) As String
Dim n, K As Integer
Dim OutText As String
If InStr(1, Left(String1, 2), Chr(7)) > 0 Then
String1 = Mid(String1, 2)
End If
If RandCode = True Then
n = Rnd(Int(DateDiff("d", ToDate, "01/01")))
Randomize (Val(Right("279", 2)))
End If
For n = 1 To Len(String1)
K = Int((117 - 6 + 3) * Rnd + 8)
OutText = OutText + Chr(Asc(Mid(String1, n, 1)) - K)
Next
Decript = OutText
End Function
any help would be most appriacated
Thank you
Lloyd Sheen - 02 Jul 2007 21:11 GMT
>I have inherited this vb6 code which i am trying to rewrite using vb.net
>2005
[quoted text clipped - 24 lines]
> any help would be most appriacated
> Thank you
First you must import:
Imports Microsoft.VisualBasic.Strings
Then use the following code:
Public Function Decript(ByVal String1) As String
Dim n, K As Integer
Dim OutText As String
If InStr(1, Microsoft.VisualBasic.Strings.Left(String1, 2), Chr(7))
> 0 Then
String1 = Mid(String1, 2)
End If
If RandCode = True Then
n = Rnd(Int(DateDiff("d", ToDate, "01/01")))
Randomize(Val(Microsoft.VisualBasic.Strings.Right("279", 2)))
End If
For n = 1 To Len(String1)
K = Int((117 - 6 + 3) * Rnd() + 8)
OutText = OutText + Chr(Asc(Mid(String1, n, 1)) - K)
Next
Return OutText
End Function
I don't know what RandCode or ToDate are supposed to be but other than that
it should work identically.
Notice that in VB.Net you use the return verb rather than assign the value
of the return to the function name as in VB6.
Hope this helps.
Lloyd Sheen
Kerry Moorman - 02 Jul 2007 21:36 GMT
Lloyd,
In VB.Net, both methods of returning a value from a function work identically.
Kerry Moorman
> Notice that in VB.Net you use the return verb rather than assign the value
> of the return to the function name as in VB6.
>
> Hope this helps.
>
> Lloyd Sheen
rowe_newsgroups - 02 Jul 2007 23:56 GMT
On Jul 2, 4:36 pm, Kerry Moorman
<KerryMoor...@discussions.microsoft.com> wrote:
> Lloyd,
>
[quoted text clipped - 8 lines]
>
> > Lloyd Sheen
> In VB.Net, both methods of returning a value from a function work identically.
Yes, but return is much better when you rename a function - a feature
I sorely missed in vb classic.
Thanks,
Seth Rowe
Cor Ligthert [MVP] - 03 Jul 2007 06:09 GMT
Lloyd,
> Yes, but return is much better when you rename a function -
I would not write "better", in my idea is it your personal preference, as it
is mine too.
:-)
Cor
> On Jul 2, 4:36 pm, Kerry Moorman
> <KerryMoor...@discussions.microsoft.com> wrote:
[quoted text clipped - 22 lines]
>
> Seth Rowe
rowe_newsgroups - 03 Jul 2007 13:25 GMT
On Jul 3, 1:09 am, "Cor Ligthert [MVP]" <notmyfirstn...@planet.nl>
wrote:
> Lloyd,
>
[quoted text clipped - 33 lines]
>
> > Seth Rowe
> I would not write "better", in my idea is it your personal preference, as it
> is mine too.
Oops, I guess I forgot my IMO tag in my previous statement.
Besides, if you and I actually agree it has to be correct right?
:-)
Thanks,
Seth Rowe
Andrew Morton - 03 Jul 2007 13:32 GMT
> In VB.Net, both methods of returning a value from a function work
> identically.
Not quite - from the help:
"Return is equivalent to assigning the expression to the function name as
the return value and then executing an Exit Function statement"
Andrew
Cor Ligthert [MVP] - 03 Jul 2007 06:08 GMT
Peter,
I am absolute no VB6 guy anymore, however just with as less changes as
possible.
You can change the Left, Mid by substring, which is in my idea easier and
common to use
string1.substring(starting where indexer is zero, length)
\\\
Public Function Decript(ByVal String1 As String, ByVal RandCode As Boolean)
As String
Dim n, K As Integer
Dim OutText As String
If InStr(1, Microsoft.VisualBasic.Left(String1, 2), Chr(7)) > 0 Then
String1 = Mid(String1, 2)
End If
If RandCode = True Then
n = CInt(Rnd(Int(DateDiff("d", Today, "01/01"))))
Randomize(Val(Microsoft.VisualBasic.Right("279", 2)))
End If
For n = 1 To Len(String1)
K = CInt(Int((117 - 6 + 3) * Rnd() + 8))
OutText = OutText + Chr(Asc(Mid(String1, n, 1)) - K)
Next
Decript = OutText
End Function
///
>I have inherited this vb6 code which i am trying to rewrite using vb.net
>2005
[quoted text clipped - 24 lines]
> any help would be most appriacated
> Thank you