Here is an XSLT stylesheet that sorts your Individual elements on the
Name child elements:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:strip-space elements="*"/>
  <xsl:output method="xml" indent="yes"/>
  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>
  <xsl:template match="IndividualListing">
    <xsl:copy>
      <xsl:apply-templates select="Individual">
        <xsl:sort select="Name" data-type="text"/>
      </xsl:apply-templates>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

Result then starts like this

<IndividualListing>
  <Individual>
    <Name>Aaron, Scott</Name>
    <Pager>3122220365@archwireless.net</Pager>
  </Individual>
  <Individual>
    <Name>Adams, Ryan</Name>
    <Pager>2129410781@archwireless.net</Pager>
  </Individual>
  <Individual>
    <Name>Anderson, Karl R.</Name>
    <Pager>3122051023@archwireless.net</Pager>
  </Individual>

You can run XSLT stylesheets from inside Visual Studio 2005 or with .NET
code where you use System.Xml.Xsl.XslCompiledTransform with .NET 2.0.

See
<http://msdn2.microsoft.com/en-us/library/system.xml.xsl.xslcompiledtransform.aspx>
VB.NET example is as easy as

Dim xslt As New XslCompiledTransform()
xslt.Load("stylesheet.xsl")

' Execute the transform and output the results to a file.
xslt.Transform("file.xml", "sorted.xml")