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.NET Forum / .NET Framework / New Users / November 2006

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XML Filter Fast Way?

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xeroxero - 06 Nov 2006 05:12 GMT
I have an XML document that I would like to remove/filter whole nodes
(and their child nodes) if an attribute is not contained/matched. I
would like to output a new XML document, not modifying the original.
Can anyone recommend XSLT for this or a programmatic way if it's
faster?

<item look="a;b">
    <item look="a;b">
        <subitem/>
        <subitem/>
        <item look="a">
            <subitem/>
            </subitem/>
        </item>
    </item>
<item>

I would like to apply an expression to the above document, so any
<item> element that does not have a "b" in the look attribute is
removed. I would like the result XML document to be:

<item look="a;b">
    <item look="a;b">
        <subitem/>
        <subitem/>
    </item>
<item>

Thanks.
Mubashir Khan - 06 Nov 2006 11:19 GMT
i guess you can use xpath queries ....

> I have an XML document that I would like to remove/filter whole nodes
> (and their child nodes) if an attribute is not contained/matched. I
[quoted text clipped - 25 lines]
>
> Thanks.
xeroxero - 06 Nov 2006 16:44 GMT
That is not going to work. The original XML document is generated
dynamically. I think I need to do XSLT or some kind of
iterative/dynamic XPath technology. Can anyone provide a sample?

>i guess you can use xpath queries ....
>>
[quoted text clipped - 27 lines]
>>
>> Thanks.

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