Pamela,

I'm using the following sub in VB:

    Public Shared Sub OpenExplorerDirectory(ByVal directoryName As String)
        Try
            Dim startInfo As System.Diagnostics.ProcessStartInfo = New
System.Diagnostics.ProcessStartInfo
            With startInfo
                .FileName = "explorer"
                .UseShellExecute = True
                .WindowStyle = ProcessWindowStyle.Normal
                .Arguments = Constants.doubleQuote & directoryName & Constants.doubleQuote
            End With
            System.Diagnostics.Process.Start(startInfo)
        Catch ex As Exception
            MessageBox.Show(ex.Message)
        End Try
    End Sub