A String Problem

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小安 - 04 Dec 2005 03:57 GMT

void myfunction(String * Parameter){
String* test0 = S"A"; // Parameter is also "A",but its details is not
very clear.

String *test1 = String::Format(S"head{0}tail",test0);
// the test1 is "headAtail"
String *test2 = String::Format(S"head{0}tail",Parameter);
// the test2 is "headA" , the charactors following A are all cut.}

I guess the Parameter has a terminative '\0' ,but I am not quite sure of
that.(The Watch Pannel shows that it is just a "A");
What 's the possible reason of this? How to avoid it?

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Jon Skeet [C# MVP] - 04 Dec 2005 07:22 GMT

<=?Utf-8?B?5bCP5a6J?= <@discussions.microsoft.com>> wrote:

> void myfunction(String * Parameter){
> String* test0 = S"A"; // Parameter is also "A",but its details is not
[quoted text clipped - 8 lines]
> that.(The Watch Pannel shows that it is just a "A");
> What 's the possible reason of this? How to avoid it?

I suspect you'll find that test2 is *actually* headA\0tail, but that
what you're using to display it is stopping as soon as it sees a \0.
The best fix for this is to try to work out why you're getting a \0 in
the first place, and avoid it. Otherwise, you can use String.Trim,
passing in \0 as the character to trim.

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小安 - 04 Dec 2005 11:49 GMT

Thank you!!

TrimEnd(S"\0"->ToCharArray()) can solve the problem.

“Jon Skeet [C# MVP]”编写：

> <=?Utf-8?B?5bCP5a6J?= <@discussions.microsoft.com>> wrote:
> > void myfunction(String * Parameter){
[quoted text clipped - 15 lines]
> the first place, and avoid it. Otherwise, you can use String.Trim,
> passing in \0 as the character to trim.

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A String Problem

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