DataGridView.CurrentCell (Set)

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Michel Walsh - 14 Feb 2008 23:32 GMT

Someone has an example, C#, about how to set the cell(int row, int col) as
the current cell for a DataGridView. The example, in the help file, about
DataGrid.CurrentCell Property (Set)

myGrid.CurrentCell = new DataGridCell(1,1);

does not work, fro a DataGridView, since we cannot create a DataGridView
Cell while specifying only its row and column.

Vanderghast, Access MVP

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Michel Walsh - 14 Feb 2008 23:41 GMT

Sorry for the bandwidth, just found that I just have to point to that said
cell, after all... doh. No need to 'create' one, as the example from
DataGrid leads us to think. The following works:

dataGridView1.CurrentCell = dataGridView1.Rows[iRow].Cells[iCol];

Vanderghast, Access MVP

> Someone has an example, C#, about how to set the cell(int row, int col)
> as the current cell for a DataGridView. The example, in the help file,
[quoted text clipped - 6 lines]
>
> Vanderghast, Access MVP

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Nicholas Paldino [.NET/C# MVP] - 15 Feb 2008 03:30 GMT

Michael,

There are more succinct ways of doing this:

dataGridView1.CurrentCellAddress = new Point(1, 1);

Or, if you wish:

dataGridView1.CurrentCell = dataGridView1[1, 1];

Both should have the same effect, although the top example will help
prevent unsharing of rows, which is good when you are using the grid in
virtual mode.

Signature

- Nicholas Paldino [.NET/C# MVP]
- mvp@spam.guard.caspershouse.com

> Sorry for the bandwidth, just found that I just have to point to that said
> cell, after all... doh. No need to 'create' one, as the example from
[quoted text clipped - 14 lines]
>>
>> Vanderghast, Access MVP

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Michel Walsh - 15 Feb 2008 14:15 GMT

If I can ask you one more question.

While

dataGridView1.CurrentCell = dataGridView1[1, 1];

is fine for me, if I consider dataGridView[1,1] is a reference (a pointer)
to an existing cell, and then CurrentCell property just 'set the focus' on
that 'object reference' it got as its 'value', I fail to see how:

dataGridView1.CurrentCellAddress = new Point(1, 1);

could even work, since

new Point(1, 1)

is also a reference, but totally unrelated to any cell-references
(cell-pointers) owned by the dataGridView object. With this, in
consideration, can you explain the inner-working of

dataGridView1.CurrentCellAddress = new Point(1, 1);

Thanks for your time
Vanderghast, Access MVP

> Michael,
>
[quoted text clipped - 9 lines]
> prevent unsharing of rows, which is good when you are using the grid in
> virtual mode.

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Nicholas Paldino [.NET/C# MVP] - 16 Feb 2008 19:06 GMT

Michel,

As you and Andrus pointed out, you the CurrentCellAddress property is
read-only, so you can't set it.

So only the first example I gave is valid.

Signature

- Nicholas Paldino [.NET/C# MVP]
- mvp@spam.guard.caspershouse.com

> If I can ask you one more question.
>
[quoted text clipped - 34 lines]
>> prevent unsharing of rows, which is good when you are using the grid in
>> virtual mode.

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Andrus - 15 Feb 2008 17:58 GMT

> dataGridView1.CurrentCellAddress = new Point(1, 1);

causes error
'System.Windows.Forms.DataGridView.CurrentCellAddress' cannot be assigned
to -- it is read only

So how to use it ?

Andrus.

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DataGridView.CurrentCell (Set)

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