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.NET Forum / Languages / C# / January 2008regular expressions help
I am trying to the values of string of text in the sample before. The ds are for digits and s is for string and string of text is for a string with more than one or two values. I am trying to use regex and the .groups method. Please help. d|d|d|string of text 1||s|s|||dd.dd|ss|string of text 2||||||||||||||||||||||||||string of text 2 I only want string of text1 I want to grab the 4th item from the entire string of this d|d|d|string of text 1||s|s|||dd.dd|ss|string of text 2||||||||||||||||||||||||||string of text 2 1|1|1|ABCDEF.....XYZ 1||A|A|||11.11|AB|ABCDEF.....XYZ 2||||||||||||||||||||||||||ABCDEF.....XYZ 2 I only need string of text 1 for display, not d|d|d|string of text 1|| s|s|||dd.dd|ss|string of text 2||||||||||||||||||||||||||string of text 2. On Jan 9, 12:14 pm, supercrossk...@gmail.com wrote: > I am trying to the values of string of text in the sample before. The > ds are for digits and s is for string and string of text is for a [quoted text clipped - 5 lines] > > I only want string of text1 I am not sure I understand the question, but I think this will help. You can create a named group by enclosing it in paranethsis and add ?<name>. For example, I have the following Regex pattern in my code "_(?<WellName>[A-H]\\d{1,2})_" This is used to capture just the Well Designation (a letter from A-H and then 1 or 2 digits) from a longer string as long as that pattern is surrounded by underscores. Regex.Match("SomeText_B7_MoreText","_(?<WellName>[A-H]\\d{1,2})_").Groups["WellName"].Value; Would return "B7" (If I don't have a typo somewhere...) Ethan > I am trying to the values of string of text in the sample before. The > ds are for digits and s is for string and string of text is for a [quoted text clipped - 5 lines] > > I only want string of text1 I will try to make it more clear. 1|2|3|this are is the text I want to display||a|b|||45.67|cd|don't need this text |||||||||||||||||||||||||| this text I've tried some combinations of things to get exactly what I want, but can't get it 100%. ([\w.]+\s*)?,?").Groups(1).ToString() only gets first item, number 1 in this case. I want the text "this are is the text I want to display" and only that. The pattern is just like it is above, the first 3 are digits, then some text(the text I want), empty, one alpha character, etc in example. On Jan 9, 3:29 pm, Ethan Strauss <EthanStra...@discussions.microsoft.com> wrote: > I am not sure I understand the question, but I think this will help. > [quoted text clipped - 24 lines] > > - Show quoted text - This is for a pipe delimited string of text using regular expressions. On Jan 10, 9:03 am, supercrossk...@gmail.com wrote: > I will try to make it more clear. > [quoted text clipped - 44 lines] > > - Show quoted text - So, are you trying to get an specific regular expression to use? The way I generally start is by describing exactly what about the pattern is unique. In this case, I think what you want is the first set of characters which does not contain any pipes (|) after 3 occurances of 1 digit 1 pipe. Is that correct? If so, try this (\d|){3}(?<TheGroupIWant>.*)| Here is what that means (\d|){3} 3 occurances of any digit followed by a pipe (?<TheGroupIWant>.*) any number of characters (except new lines) captured into a group named "TheGroupIWant" | A pipe (so it stops this group as soon as a pipe occurs. ) Ethan > This is for a pipe delimited string of text using regular expressions. > [quoted text clipped - 47 lines] > > > > - Show quoted text - That makes sense, but it does not work. This is VB.net Dim stringofText As String = "9|1|1|Today is a great day|1" Response.Write( Regex.Match( stringofText, "(\d|){3}(? <TheGroupIWant>.*)| ").Groups(1).ToString() ) I did get it to work be doing a split and an array. I wouldn't mind figuring out the regex way to do it too. On Jan 10, 10:23 am, Ethan Strauss <EthanStra...@discussions.microsoft.com> wrote: > So, are you trying to get an specific regular expression to use? The way I > generally start is by describing exactly what about the pattern is unique. In [quoted text clipped - 70 lines] > > - Show quoted text - If I do Dim stringofText As String = "9|1|1|Today is a great day|1" Response.Write( Regex.Match( stringofText, "(\d|){3}(? <TheGroupIWant>.*)| ").Groups("TheGroupIWant").ToString() ) I get 9|1|1|Today is a great day|1, not Today is a great day On Jan 10, 10:23 am, Ethan Strauss <EthanStra...@discussions.microsoft.com> wrote: > So, are you trying to get an specific regular expression to use? The way I > generally start is by describing exactly what about the pattern is unique. In [quoted text clipped - 70 lines] > > - Show quoted text - You have to escape the pipe with a \. Dim stringofText As String = "9|1|1|Today is a great day.|1" Response.Write( Regex.Match( stringofText, "(\d\|){3}(? <TheGroupIWant>.*)\|").Groups("TheGroupIWant").ToString() ) That works just fine. On Jan 11, 11:23 am, supercrossk...@gmail.com wrote: > If I do > [quoted text clipped - 83 lines] > > - Show quoted text - It doesn't work with more data at the end, like this. Dim stringofText As String = "4|1|3|have a nice day.||a|b|||12.34|ab| abcdefg||||||||||||||||||||||||||ACBDEFG123456789" Response.Write( Regex.Match( stringofText, "(\d\|){3}(? <TheGroupIWant>.*)(\w?|\s?\|)?").Groups("TheGroupIWant").ToString() ) On Jan 11, 12:20 pm, supercrossk...@gmail.com wrote: > You have to escape the pipe with a \. > [quoted text clipped - 95 lines] > > - Show quoted text - Sorry, I actually tested it this time, so it works for sure for me. String text = "4|1|3|have a nice day.||a|b|||12.34|ab|abcdefg||||||||||||||||||||||||||ACBDEFG123456789"; string Results = Regex.Match(text, @"(\d\|){3}(?<TheGroupIWant>[^\|]*)").Groups["TheGroupIWant"].ToString(); Gives "have a nice day." It looks like you are using VB, so your syntax is a little different, but anyway, the "[^\|]" means Anything except a pipe. Ethan > It doesn't work with more data at the end, like this. > [quoted text clipped - 103 lines] > > > > - Show quoted text - Free MagazinesGet these publications absolutely FREE for up to 12 months. There are no hidden fees and no obligation. Simply choose a title, complete the application form and submit it. Read more ...
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