Bitwise operation returning a long ... how

Thread view:

Enable EMail Alerts

Start New Thread

Thread rating:

DaTurk - 27 Aug 2007 02:26 GMT

int number = 0;
int result = 0;

result = number | 0x80000000

Why is the compiler telling me this is converting a long to an int.
Where's the long? 0x80000000 is 32 bits, what am I missing?

Reply to this Message

Arne Vajhøj - 27 Aug 2007 02:37 GMT

> int number = 0;
> int result = 0;
[quoted text clipped - 3 lines]
> Why is the compiler telling me this is converting a long to an int.
> Where's the long? 0x80000000 is 32 bits, what am I missing?

0x80000000 is an uint (not an int).

And apperently int | uint gives a long.

Arne

Reply to this Message

Michael C - 27 Aug 2007 02:56 GMT

>> Why is the compiler telling me this is converting a long to an int.
>> Where's the long? 0x80000000 is 32 bits, what am I missing?
>
> 0x80000000 is an uint (not an int).
>
> And apperently int | uint gives a long.

This is a bit of a pita in C# imo when defining constants etc.

Michael

Reply to this Message

Ben Voigt [C++ MVP] - 28 Aug 2007 21:54 GMT

> int number = 0;
> int result = 0;
[quoted text clipped - 3 lines]
> Why is the compiler telling me this is converting a long to an int.
> Where's the long? 0x80000000 is 32 bits, what am I missing?

If you think that's fun, try:

byte a, b, c;
a = 1;
b = 5;
c = a & b;

Reply to this Message

Bitwise operation returning a long ... how

Free Magazines