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.NET Forum / Languages / C# / June 2007Declaring an array of List Generic Class elements
Hello, I am declaring an element like this: public static List<myListElement> myList = new List<myListElement>(); I would like to declare an array of this myList. How would I modify the declaration of myList so it will represents an array? Thanks Eitan > Hello, > [quoted text clipped - 7 lines] > Thanks > Eitan public static List<myListElement>[] myList = new List<myListElement>[4]; Colin =^.^= Hello Colin, Thank you for your answer. I tried the line below (before posting my question): public static List<myListElement>[] myList = new List<myListElement>[4](); The difference is the brackets "()" after "[4]". The compiler generated an error. Can you explain to me why the error, and when would you need the brackets "()"? Thank you, Eitan > > Hello, > > [quoted text clipped - 11 lines] > > Colin =^.^= > Hello Colin, > Thank you for your answer. [quoted text clipped - 26 lines] >> >> Colin =^.^= Hi Eitan, If you take a look at my response it may be a bit clearer what is going on. When you're defining the array, you aren't constructing the List<> objects, just constructing an array of list objects. Parentheses are not required for constructing an array, as the construction doesn't take parameters, only a size of array to create given in the square brackets. So, that being the case, you'll have to manually construct each List<> object in your array.  SignatureTom Spink University of Edinburgh Tom, Thank you on both of your answers! Eitan > > Hello Colin, > > Thank you for your answer. [quoted text clipped - 37 lines] > So, that being the case, you'll have to manually construct each List<> > object in your array. > Hello, > [quoted text clipped - 7 lines] > Thanks > Eitan Hi Eitan, You can declare it like this: public static List<myListElement>[] listArray = new List<myListElement>[10]; (To define an array of size 10) But please note that each element in the array will still have to be constructed. You could this in a for-loop: /// for (int i = 0; i < listArray.Count; i++) listArray[i] = new List<myListElement>(); /// SignatureTom Spink University of Edinburgh Thank you! > > Hello, > > [quoted text clipped - 22 lines] > listArray[i] = new List<myListElement>(); > /// Free MagazinesGet these publications absolutely FREE for up to 12 months. There are no hidden fees and no obligation. Simply choose a title, complete the application form and submit it. Read more ...
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