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.NET Forum / .NET Framework / CLR / March 2008Array.CreateInstance failure
Hello, Bellow is a little except that creates a static array dynamically. However it creates a two dimensional one instead of a single dimensional. Why???? public static void Main(string[] args) { int[] intArray = new int[]{2,3}; Type type = intArray.GetType(); Array array = Array.CreateInstance(type, 0); // array is a two dimensional array. Why? intArray = (int[]) array; // Throws InvalidCastException, as expected Console.WriteLine(); } > Bellow is a little except that creates a static array dynamically. However > it creates > a two dimensional one instead of a single dimensional. Why???? Because you've said you want an array where each element is of type int[]. If you want the overall array to be int[], use Array.CreateInstance(typeof(int), 0)  SignatureJon Skeet - <skeet@pobox.com> http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet World class .NET training in the UK: http://iterativetraining.co.uk > Hello, > [quoted text clipped - 11 lines] > Console.WriteLine(); > } It isn't a two dimensional array. You can test that int[,] array2d = (int[,]) array; // InvalidCastException and array.Rank will be 1, not 2. In fact it is a one dimensional array where the element type is intArray.GetType() as you requested, that is each element is an array. This array-of-arrays is sometimes called a jagged array. If you want an array of the same type as the first array, use intArray.GetType().MemberType Thanx for the answers to both Ben and Jon, you were absolutely correct. > > Hello, > > [quoted text clipped - 27 lines] > If you want an array of the same type as the first array, use > intArray.GetType().MemberType
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