Hello,
I'm porting some existing C++ code to VS2005 C++/CLI.

When I compile the following code with "No CLR support" it behaves as
expected (1 + 2 = 3) in all cases.  When I compile it with /clr then
transform call using addFunc<int> suggests that 1 + 2 = 8b001cc4.

Anyone know what's going on?

Thanks,
Richard.

#include <iostream>
#include <vector>
#include <algorithm>
#include <functional>

using namespace std;

// fixed type addition function.
int addInt32Func(const int& lhs,const int& rhs)
{
 return lhs + rhs;
}

// template version of addition function
template<typename T> T addFunc(const T& lhs,const T& rhs)
{
 return lhs + rhs;
}

// functor version of addition function
template<typename T> class addClass : public binary_function<T, T, T>
{
public:
 result_type operator()(
   const first_argument_type& lhs,
   const second_argument_type& rhs)
 {
   return (result_type)(lhs + rhs);
 }
};

int main(int argc, char* argv[])
{
 cout << "Single values " << endl;

 int a = 1, b = 2, c;

 c = addInt32Func(a, b);
 cout << "  addInt32Func           "
   << hex << a << " + " << b << " = " << c << endl;

 c = addFunc<int>(a, b);
 cout << "  addFunc<int>           "
   << hex << a << " + " << b << " = " << c << endl;

 c = addClass<int>()(a, b);
 cout << "  addClass<int>::addFunc "
   << hex << a << " + " << b << " = " << c << endl;

 cout << "Transform vector values" << endl;

 const int  = 2;
 vector<int> av(N_ELEM, 1), bv(N_ELEM, 2), cv(N_ELEM);
 
 std::transform(av.begin(),av.end(),bv.begin(),cv.begin(),addInt32Func);
 cout << "  addInt32Func           "
   << hex << av[0] << " + " << bv[0] << " = " << cv[0] << endl;

 std::transform(av.begin(),av.end(),bv.begin(),cv.begin(),addFunc<int>);
 cout << "  addFunc<int>           "
   << hex << av[0] << " + " << bv[0] << " = " << cv[0] << endl;

 std::transform(av.begin(),av.end(),bv.begin(),cv.begin(),addClass<int>());
 cout << "  addClass<int>()        "
    << hex << av[0] << " + " << bv[0] << " = " << cv[0] << endl;
}