I'm compiling a list of XML files I want to open, from a database.
These XML files all have an XSLT associated with them. Now I know how
to add a XML control and configure it, but how do I do it in code?
It's my understanding that each XML document will need it's own XML
control to bind to. I need to code it, because the number of files I
get back from my query may vary, and I can't have too few / many XML
controls on my page.
Patrice - 21 May 2008 14:50 GMT
My first though would be something such as a "repeater control" that allows
to repeat a particular template for each data row it is binded to so if you
bind to a list of xml documents it will create a row for each of these
document...
Not sure what is this "XML control" you are talking about in particular once
rendered client side. If it does something client side another option could
be to just do the transformation server side and display the result...
--
Patrice
"Chris" <coz1978@gmail.com> a écrit dans le message de groupe de discussion
: 551e7833-3ad2-48d8-843e-3a1234461721@s50g2000hsb.googlegroups.com...
> I'm compiling a list of XML files I want to open, from a database.
[quoted text clipped - 4 lines]
> get back from my query may vary, and I can't have too few / many XML
> controls on my page.