specifying datavaluefield in ddlb

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SandpointGuy - 27 Sep 2007 20:17 GMT

I have a dropdown of states that is populated from a table, that looks like
ddlb.DataValueField="StateCode" // ex: FL
ddlb.DataTextField="StateDescription" // ex: Florida

If I want to set the initial value I can use
ddlb.SelectedValue="Florida"
In other words, SelectedValue is the DataTextField

How do I set the initial value to the DataValueField?
ddlb.SelectedValue="FL" doesnt work (or is it just me?)

Thanks, Mark

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Mike - 27 Sep 2007 20:20 GMT

you can do

dd.SelectedText = "FL";

is the value for Florida acutally FL?

Mike

>I have a dropdown of states that is populated from a table, that looks like
> ddlb.DataValueField="StateCode" // ex: FL
[quoted text clipped - 8 lines]
>
> Thanks, Mark

Reply to this Message

SandpointGuy - 27 Sep 2007 20:43 GMT

There is no SelectedText property for the drop down list box.

> you can do
>
[quoted text clipped - 16 lines]
> >
> > Thanks, Mark

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Mike - 27 Sep 2007 20:56 GMT

try this:
dd.SelectedItem.Text = "FL";

or if you know the index number of Fl you can do

dd.SelectedIndex = 5 (or whatever FL is)

Mike

> There is no SelectedText property for the drop down list box.
>
[quoted text clipped - 19 lines]
>> >
>> > Thanks, Mark

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SandpointGuy - 27 Sep 2007 21:28 GMT

Actually, SelectedItem.Value is closer to what I want. But it adds a new
entry at the top, rather than selecting the existing value of "FL"

In other words, I get :
<option value="FL" selected="selected" value="FL">Alabama
<option value="AL">Alabama
... other states
<option value="FL">Florida

And what I want is:
<option value="FL" selected="selected">Florida
<option value="AL">Alabama
... other states

> try this:
> dd.SelectedItem.Text = "FL";
[quoted text clipped - 28 lines]
> >> >
> >> > Thanks, Mark

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specifying datavaluefield in ddlb

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