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.NET Forum / ASP.NET / General / September 2007need help with understanding this little bit of code
According to some of the programmers that use to work here and on this code, it was done in VB and .NET Can anyone explain what the letter c and the number 1 in this line of code stand for? UID = User.Identity.Name.Split("\"c)(1)  SignatureASP, SQL2005, DW8 VBScript > According to some of the programmers that use to work here and on this > code, it was done in VB and .NET [quoted text clipped - 3 lines] > > UID = User.Identity.Name.Split("\"c)(1) User.Identity.Name will ordinarily return DOMAIN\UserID The above code is splitting that into an array based on the "\" character, and then returning the second element in that array (arrays are zero-based by default)... SignatureMark Rae ASP.NET MVP http://www.markrae.net so if i understand your reply... If a user logs in as mydomain\jsmith Splits it into mydomain jsmith So based on that code.. what SHOULD happen to a user that has a numerical value in there userid? jsmith2 Reason im asking, is it seems that if a user has a numerical value in there ID it ignores that number and defaults to anyone else with a similar ID So the following 2 people exist here jsmith jsmith2 It seems to be ignoring the 2 and defaults to jsmith So is the letter c in the code looking at just strickly characters? if so what can we use to take characters and numbers? SignatureASP, SQL2005, DW8 VBScript > >> According to some of the programmers that use to work here and on this [quoted text clipped - 10 lines] > and then returning the second element in that array (arrays are zero-based > by default)... Daniel, "a"c in vb.net distinguishes the char type from the string type. Char type represents any single unicode character (a letter, a digit, + - \ / space, return, $ % etc.) whilst string is a sequence of many characters (simplifying string is an array of Char-s). "\"c represents backslash character. (1) is the second element (because this is zero-index based array) in the array of strings returned from Split() function. It shouldn't skip numeric characters. Try dim result as String() = User.Identity.Name.Split(new Char() { "\"c } ) dim domain as string = result(0) dim user as string = result(1) if result.Length > 0 then domain = result(0) if result.Length > 1 Then user = result(1) end if end if HTH SignatureMilosz > According to some of the programmers that use to work here and on this code, > it was done in VB and .NET [quoted text clipped - 3 lines] > > UID = User.Identity.Name.Split("\"c)(1) With that said.. would there be any reason why the code would be ignoring users with numerical values in there userid? Im just trying to figure out if the code is ignoring the number in the id and defaulting to the first person that meets thefirst part of the name... jdoe ( Joe Doe ) jdoe2 ( John Doe ) even though the user names are similar everything is unique When jdoe logs in.... he gets access to jdoe2 data SignatureASP, SQL2005, DW8 VBScript > Daniel, > [quoted text clipped - 31 lines] >> >> UID = User.Identity.Name.Split("\"c)(1) Hi Daniel, I think everything is ok with the code you posted. I suspect there's a dodgy logic before/afterwards. Have you debugged the code so you can confirm numeric character(s) are truncated. Could you please paste a bigger chunk of code so we could have a look? Regards SignatureMilosz > With that said.. would there be any reason why the code would be ignoring > users with numerical values in there userid? [quoted text clipped - 43 lines] > >> > >> UID = User.Identity.Name.Split("\"c)(1) Here is more of the code: ( this is bits of the code.... ) Private Sub GetPrefixInfo() 'Put user code to initialize the page here Dim occAssocInfo As cAssocInfo = New cAssocInfo() Dim odsPrefixInfo As dsPrefixData = New dsPrefixData() Dim selAlpha As Char 'Get Store ID, Employee and Contractor Prefixes odsPrefixInfo = occAssocInfo.GetPrefix() Session.Clear() Session("iEmpPrefix") = odsPrefixInfo.usp_GetPrefix(0).emp_prefix Session("iContrPrefix") = odsPrefixInfo.usp_GetPrefix(0).contr_prefix Session("sBarCodeDir") = odsPrefixInfo.usp_GetPrefix(0).seq_descr Session("PageID") = "Main" Session("iStoreID") = iStoreID Session("UIDType") = UIDType -------------------------- Function getStoreNumberFromIP() Dim sIPAddress As String Dim iSplitID As Integer sIPAddress = Request.ServerVariables("REMOTE_ADDR") iSplitID = CInt(sIPAddress.Split("."c)(1)) 'Identify all valid store id If iSplitID < 2 Or iSplitID > 99 Then iSplitID = 999 End If Return iSplitID End Function ---------------------------------------- 'Find the user on the email list Try GRSearch.Filter = "(&(objectCategory=user)(mail=" & UID & "*))" oResults = GRSearch.FindAll() 'Determine if the user is in the group of valid users For Each oResult In oResults For iMemCount = 0 To oResult.GetDirectoryEntry().Properties("memberOf").Count - 1 strMember = oResult.GetDirectoryEntry().Properties("memberOf")(iMemCount) iEqlIdx = strMember.IndexOf("=", 1) iComIdx = strMember.IndexOf(",", 1) strGroupName = strMember.Substring(iEqlIdx + 1, (iComIdx - iEqlIdx) - 1) 'Check if the Group is a valid user or not If strGroupName = GRAdminGroup Then UIDType = "Admin" bValid = True End If If strGroupName = GRUserGroup Then UIDType = "User" bValid = True End If 'Check if there is a Store Group for the user If Len(strGroupName) >= 7 Then If UCase(strGroupName.Substring(0, 5)) = "STORE" Then 'Extract StoreID If IsNumeric(strGroupName.Substring(5, 2)) Then iStoreID = CInt(strGroupName.Substring(5, 2)) End If End If End If Next Next Catch e1 As Exception Return False End Try ================================================ This is not in order, but the bits the seem to have to do with the validating the user... thanks. SignatureASP, SQL2005, DW8 VBScript > Hi Daniel, > [quoted text clipped - 58 lines] >> >> >> >> UID = User.Identity.Name.Split("\"c)(1) Howdy, what about this line?: GRSearch.Filter = "(&(objectCategory=user)(mail=" & UID & "*))" Seems wjen the lgon is john, it will apply the logic for any john* (i.e. john2) My advice would be to debug the original line UID = User.Identity.Name.Split("\"c)(1) to see value of the UID just after the statement has been executed. But my gut feeling is the line i have just pointed out is the source of your issue. HTH SignatureMilosz > Here is more of the code: ( this is bits of the code.... ) > Private Sub GetPrefixInfo() [quoted text clipped - 189 lines] > >> >> > >> >> UID = User.Identity.Name.Split("\"c)(1) Thank you for the suggestion, i will continue to pester the old programmers that are still here to see if they know where the original code is so we can test on another server... thanks SignatureASP, SQL2005, DW8 VBScript > Howdy, > [quoted text clipped - 212 lines] >> >> >> >> >> >> UID = User.Identity.Name.Split("\"c)(1)
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