xml nodes and getting random node

Thread view:

Enable EMail Alerts

Start New Thread

Thread rating:

pelegk1 - 31 Jul 2007 23:22 GMT

i have an xml for example:
<xml>
<data>
<var>xxx</var>
</data>
<tip>
<tips active="1">345</tips>
<tips active="1">retertert</tips>
<tips active="1">fdgdfg</tips>
<tips active="0">ert435345</tips>
<tips active="1">fdgdf</tips>
<tips active="1">dfgdfg</tips>
<tips active="0">gdfgdfg</tips>
<tips active="1">dfgdfg</tips>
<tips active="1">dfgdfg</tips>
</tip>
</xml>

and i want to get only the nodes that active="1" and get from then a radnom
one (to get actually its text() )
how can i do this?
thnaks in advance
peleg

Reply to this Message

Alexey Smirnov - 01 Aug 2007 11:35 GMT

> i have an xml for example:
> <xml>
[quoted text clipped - 19 lines]
> thnaks in advance
> peleg

Try this

XmlNodeList nodes = xmlDoc.SelectNodes("//tip/tips[@active='1']");

Random r = new Random();
int x = r.Next(0, nodes.Count);
int i = 0;

foreach(XmlNode node in nodes) {
if (i == x) {
     here's your code
     ...
     return;

} else {
     x++;
}
}

Reply to this Message

Free Magazines

Get these publications absolutely FREE for up to 12 months. There are no hidden fees and no obligation. Simply choose a title, complete the application form and submit it. Read more ...