Hi Brent,

Starting a newline is \r\n on dos/windows systems.

So if you use
"-*?\r\n"
on
"----------------------------------------
"
"----------------------------------------
"

It will match 2 times.

A caution is maybe in order here. If you use a lazy non greedy quantifier
it will match the shortest string possible.

So if you let the regex
-*?
Loose on 5 times a dash
-----
The result will be 6 *empty* matches : m-m-m-m-m-m

Whe empty? bacause the star in your regex allows 0 occurences. So the shortest
string possible is the empty string.

Compare this with the regex
-*?a
on
-----a

Now you want an a to be at the end of a match so the shortest string possible
is now : -----a
This is the whole original input string and this is the only match.

You say you want a windows newline so your doing fine.

Let me know if you have any more questions..

Cheers,
Tom Pester

Try:

-+\r\n

Not sure what you were trying to accomplish with your *?
(literally:zero or more, possibly.)  That would always match any new
line, assuming you used \r or \r\n as your newline character.

Jason Kester
Expat Software Consulting Services
http://www.expatsoftware.com/